Is there a format in MATLAB to display numbers such that commas are automatically inserted into the display?

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MathWorks Support Team
编辑： MathWorks Support Team 2024-2-29
I would like to display large numbers with commas separating the digits for readability purposes. For example, I would like MATLAB to display one billion as 1,000,000,000 rather than 1000000000. How can I do this?

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采纳的回答

MathWorks Support Team
编辑：MathWorks Support Team 2024-2-29
You can enhance the readability of large numbers by formatting them with commas to separate digits using the "java.text.DecimalFormat" class. See the below code for an example of this:
function numOut = addComma(numIn)
import java.text.*
jf=java.text.DecimalFormat; % comma for thousands, three decimal places
numOut= char(jf.format(numIn)); % omit "char" if you want a string out
end
Then, calling the function will result in a comma separated number.
addComma(10000.12)
% 10,000.12

更多回答（2 个）

Ted Shultz
Ted Shultz 2018-6-13
A simple way is to add this two line function:
function numOut = addComma(numIn)
jf=java.text.DecimalFormat; % comma for thousands, three decimal places
numOut= char(jf.format(numIn)); % omit "char" if you want a string out
end
Hope that helps! --ted
Toshiaki Takeuchi
Toshiaki Takeuchi 2023-11-14
Ran in:
Using pattern
vec = 123456789;
txt = string(vec);
pat1 = lookBehindBoundary(digitsPattern); % (?<=\d)
pat2 = asManyOfPattern(digitsPattern(3),1); % (\d{3})+
pat3 = lookAheadBoundary(pat2+lineBoundary("end")); % (?=(\d{3})+$)
pat4 = pat1+pat3; % (?<=\d)(?=(\d{3})+$)
replace(txt,pat4,",")
ans = "123,456,789"
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显示 1更早的评论
Toshiaki Takeuchi
Toshiaki Takeuchi 2024-1-30
Ran in:
How about this?
str = arrayfun(@(x) string(num2str(x)), (0:500:2000)');
str2 = [str;str + ".12345"]
str2 = 10×1 string array
"0" "500" "1000" "1500" "2000" "0.12345" "500.12345" "1000.12345" "1500.12345" "2000.12345"
pat1 = lookBehindBoundary(digitsPattern); % (?<=\d)
pat2 = asManyOfPattern(digitsPattern(3),1); % (\d{3})+
pat3 = lookAheadBoundary(pat2+lineBoundary("end")); % (?=(\d{3})+$)
pat4 = pat1+pat3; % (?<=\d)(?=(\d{3})+$)
isDecimal = contains(str2,".");
str3 = split(str2(isDecimal),".");
str2(isDecimal) = str3(:,1);
str4 = replace(str2,pat4,",");
str4(isDecimal) = str4(isDecimal) + "." + str3(:,2)
str4 = 10×1 string array
"0" "500" "1,000" "1,500" "2,000" "0.12345" "500.12345" "1,000.12345" "1,500.12345" "2,000.12345"
Stephen23
Stephen23 2024-2-10
编辑：Stephen23 2024-2-10
Ran in:
That seems to work much better. Note that this
str0 = arrayfun(@(x) string(num2str(x)), (0:500:2000)');
can be replaced with the much simpler and more efficient:
str1 = string(0:500:2000).';
isequal(str0,str1)
ans = logical
1

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