for loop in parfor
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I want to use a for-loop inside parfor, is it possible? If not what is the alternative?
Thanks,
采纳的回答
Edric Ellis
2011-6-17
Yes, it's possible. For example,
parfor ii=1:10
for jj=1:10
x(ii,jj) = rand
end
end
Note that this example is so computationally trivial that it is much slower than a serial version.
6 个评论
Mohamed
2011-6-17
Walter Roberson
2011-6-17
If I remember correctly, the actual plotting all goes through the same thread. I do not know, though, if that extends to updating the properties of existing plot objects: I think for consistency that would have to go through the single thread too.
Benoit
2012-6-29
Hello,
I actually have problems with the above code as I get the message that the variable x cannot classified.
??? Error: The variable x in a parfor cannot be classified. See Parallel for Loops in MATLAB, "Overview".
There must be that variable x must be defined somehow. Any help appreciated.
Thanks!
Walter Roberson
2012-6-29
In a recent thread we have been discussion whether the workers have access to graphics at all (I don't have the toolbox to check myself.) The evidence is suggestive that the workers do not have graphics access, but I have not happened to read any definite statement of that.
Edric Ellis
2012-7-2
@Benoit - which version are you running? The ability to recognise 'x' as a sliced variable was added relatively recently.
@Walter - matlabpool workers (either local workers with PCT or cluster workers with MDCS) have no visible graphics of their own. However, they can generate off-screen graphics and call 'print' to files.
Hi Edric, I am trying to run a slightly modified script:
a = linspace(0,10);
parfor ii=1:10
for jj=1:length(a)
x(ii,jj) = rand;
end
end
However, Matlab complains about the x variable classification. But I don't quite understand, why it shouldn't work. Any ideas? Thanks in advance, Niels.
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