Removing a specific number from vector
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Hi Everyone,
Suppose I have the following
A = 4
and
Z = [1 9 2 3 4 5]
how do I remove the value A from Z, to get
Z = [1 9 2 3 5]
Regards,
Ulrik.
回答（4 个）
Gurudatha Pai
2011-6-17
A = 4;
Z = [1 9 2 3 4 5]
Z1 = Z(find(Z~=A))
that should work
Walter Roberson
2011-6-17
Z(Z==A) = [];
Warning: if you have floating point numbers instead of integers, you will usually need to compare with a tolerance instead of ==
Tiasa Ghosh
2018-7-25
You can also use setdiff function.
a=4;
z=[1 9 2 3 4 5];
setdiff(z,a)
2 个评论
Gospel Oh
2018-11-15
If the function were to be put into MatLab, the answer actually comes out to be an ordered version, missig the a:
ans = 1 2 3 5 9
close, but not quite
Paul Smits
2019-4-26
You may pass 'stable' as additional input to setdiff, to prevent sorting:
a=4;
z=[1 9 2 3 4 5];
setdiff(z,a,'stable')
Richard Barrett-Jolley
2018-7-13
Yes, that would work, but I would recommend simply:
Z=Z(Z~=A);
4 个评论
Walter Roberson
2018-7-17
I don't think I've seen anyone benchmark expressing as a subset copy, compared to expressing as a deletion such as I did.
Personally I find the deletion easier to read.
Walter Roberson
2019-4-30
My testing suggests that Z=Z(Z~=A) is faster than deleting from Z, taking about 82% as long, at least for longer arrays.
huda nawaf
2022-8-7
HI
Im facing the same problem, but the size of A is more than one.
so Z=Z(Z~=A); does not work. Is there an alternative?
Thanks
Walter Roberson
2022-8-8
Z = Z(~ismember(Z, A));
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2011-6-17
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