Why do I get unexpected errors when using NaN values in INTERP1?
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Why do I get unexpected errors when using NaN values in INTERP1?
Using the INTERP1 function of MATLAB 6.1 (R12.1) with NaN values returns an unusual error:
interp1([NaN 1:4],[2:6],3.5)
??? Index into matrix is negative or zero. See release notes on changes to
logical indices.
Error in ==> D:\Applications\MATLAB\toolbox\matlab\polyfun\interp1.m
On line 157 ==> s = u - x(k);
This error can be traced to the results of the HISTC function called earlier within INTERP1:
[n,k] = histc(3.5,[NaN 1:4])
n =
0 0 0 0 0
k =
0
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MathWorks Support Team
2009-6-27
0 个投票
This bug has been fixed for Release 14 (R14). For previous releases, please read below for any possible workarounds:
INTERP1 is not intended to handle NaN's as input, since NaN values cannot be placed in increasing order (a requirement of INTERP1 and of HISTC). As a workaround, use Inf or -Inf to represent a limit.
Our development staff has been notified and is currently looking into addressing this problem in a future release of MATLAB.
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2009-6-27
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