According to Gregorian Calender(which is in use now, in many countries),decide whether a given year is a leap year or not. Give 'true' if the given year is a leap year and 'false',if not.
Note: In the Gregorian calendar 3 criteria must be taken into account to identify leap years:
The year is evenly divisible by 4; If the year can be evenly divided by 100, it is NOT a leap year, unless; The year is also evenly divisible by 400. Then it is a leap year.
Solution Stats
Problem Comments
3 Comments
Solution Comments
Show comments
Loading...
Problem Recent Solvers193
Suggested Problems
-
1439 Solvers
-
Find the largest value in the 3D matrix
1663 Solvers
-
302 Solvers
-
560 Solvers
-
Finding an element in a vector
203 Solvers
More from this Author1
Problem Tags
Community Treasure Hunt
Find the treasures in MATLAB Central and discover how the community can help you!
Start Hunting!
Kumar, in problem #4 there is one to many right parenthesis. George...
Actually I just realized it is the "isequal" is missing in test #4.
Thanks George.Am extremely sorry for that.I just corrected it.