That's not the correct definition of the concept of "weighted average". Instead, it's rather the average product of two data vectors x and w.
I agree with yurenchu. If you want to choose Problems to translate, then first read all comments made about the original Problem statement to see if there are any important critiques to heed. If so, then either address the critiques and create an improved version of the Problem, or else choose a different original Problem.
Changed the translation
Very good :-)
Distance walked 1D
Roll the Dice!
Fibonacci-Sum of Squares
Perimeter of a semicircle
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