Borrowing the idea from Pascal Triangle, the following operation can be performed. Starting with an array of numbers from 1 to N (where N is greater than 1), the following upside-down triangle of numbers can be formed where starting from the second row, the number is determined by adding the two neighboring numbers in the previous row.
Given N, determine the sum of all numbers in the triangle.
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I think the description may be more appropriate to say the 'sum of all the numbers in the triangle'.
Problem statement updated.