This code tried to find if the entered number(number greater than 100) can be split into 3 parts such that, the 3rd part will be the sum of the 1st and 2nd part.
Let abc be the number, then if a + b = c, abc passes.

Example 1:
Number = 9999198
99+99=198

Example 2:
Number= 123
1 + 2 = 3

Example 3:
Number= 201800012019
2018 + 0001 = 2019

Example for fail:
Number = 451
the sum would never result into 1.

Number= 2010000001
No combination will be able to spit the number such that the sum of first 2 part would be equal to the 3rd part.