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Assignment has more non-singleton rhs dimensions than non-singleton subscripts
ode
8 years 前 | 1 个回答 | 0
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second order differential equation are arranged in ring
mi (d^tδi/dt^2) + di(dδi/dt) = pmi − b sin(δi) − bint [sin(δi − δi+1) + sin(δi − δi−1)] where mi=1,di=0.3,b=1,bint=100,pmi=0.95...
8 years 前 | 1 个回答 | 1
