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Sarvjeet Singh


Last seen: 2 years 前 |  自 2019 起处于活动状态

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what is the problem with this code gauss siedel . Only processing one solution but it should be twenty solutions
clc clear all area=0.01; % Cross sectional area (m^2) l=1; % Length of the rod (m) k=5; % Thermal conductivity (W/mK) g=2...

3 years 前 | 0 个回答 | 0

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Steepest descent method , how to fix this error "Struct contents reference from a non-struct array object."
error shows 'Index exceeds matrix dimensions.', how to fix clc clear all %%%%%%%%%%%%%%%%Steepest Descent %%%%%%%%%%%%%%%5 a...

4 years 前 | 0

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Steepest descent method n shows error 'Index exceeds matrix dimensions.', how to fix this
clc clear all %%%%%%%%%%%%%%%%Steepest Descent %%%%%%%%%%%%%%%5 ao=1; bo=0.2; co=0.1; x = [0 0.2 0.4 0.6 0.8 1.0 1.2 1.4 1...

4 years 前 | 1 个回答 | 0

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Steepest descent method , how to fix this error "Struct contents reference from a non-struct array object."
ao=1; bo=0.2; co=0.1; x = [0.9 1.5 13.8 19.8 24.1 28.2 35.2 60.3 74.6 81.3]; y= [455.2 428.6 124.1 67.3 43.2 28.1 13.1 -0.4 ...

4 years 前 | 2 个回答 | 0

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How to use the steepest descent method to solve a function to find the unknown parameters value
why it shows error,please fix this ao=1; bo=0.2; co=0.1; x = [0.9 1.5 13.8 19.8 24.1 28.2 35.2 60.3 74.6 81.3]; y= [455.2 4...

4 years 前 | 1 个回答 | 0

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How to use the steepest descent method to solve a function to find the unknown parameters value
why it shows error,please fix this ao=1; bo=0.2; co=0.1; x = [0.9 1.5 13.8 19.8 24.1 28.2 35.2 60.3 74.6 81.3]; y= [455.2...

4 years 前 | 1 个回答 | 0

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whenever i use individual value of time (Tv) the output function (F) giving right value but using time in the form of loop ,output function gives wrong result for all.How to fix this ?
clc clear all c1 = 3.742*10.^8; c2 = 1.43878*10.^4; sigma = 5.67*10.^-8; lamda_1 = 8; lamda_2 = 13; Tv = -10:5:30; F = z...

4 years 前 | 1 个回答 | 0

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Why F vs T graph are not plotted , it shows only blank figure and how i can get all the values of F and T in the workspace as it shows only last value.
c1 = 27.742*10.^8; c2 = 1.43878*10.^4; sigma = 5.67*10.^-8; T = 5780; lamda_1 = 8; lamda_2 = 13; for T=-10:5:30 fun = @...

4 years 前 | 2 个回答 | 0

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Integrate planck function between two intervals
function Planck_law c1=27.742*10.^8; c2=1.43878*10.^4 sigma=5.67*10.^-8 T=5780 lamda_1= 8 lamda_2= 13 fun= @(lambda,sigm...

4 years 前 | 1 个回答 | 0

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How to use pdepe function to solve interface boundary problem in bio heat transfer problem.
p,q=?

5 years 前 | 0 个回答 | 0

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