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loop and array for sum
magnitude= abs(y); % amplitude of y signal near= ceil(N/F); signal= zeros(1,near); for i=1:1000:N for j=i:1:near s...
5 years 前 | 2 个回答 | 0
2
个回答提问
abs sample magnitude sum
Hello, I wrote the code as shown below : [y,fs]= audioread(file); info= audioinfo(file); [P,Q]= rat(1000/fs); Fnew= P/Q*fs; ...
5 years 前 | 1 个回答 | 0
