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pointsToWorld distance measurement is very off.
I am using this as a reference. I take two pixel coordinates from undistorted image and apply them into pointsToWorld, then find...
4 years 前 | 0 个回答 | 0
0
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"Index exceeds matrix dimensions." But it doesn't
Masks=[0 1 0;... 1 -4 1;... 0 1 0;]; a=imread('C:\Users\***\Desktop\Matlab\figure\Fig3.40(a).jpg'); x=size(a); m=...
6 years 前 | 1 个回答 | 0
1
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How do I put this formula int matlab?
z=imread('C:\Users\*****\Desktop\Matlab\Homework 3-02 03 04 05\Fig308a.jpg'); for i=1:255 y(i)=sum(z(:) == i); end n=488...
6 years 前 | 1 个回答 | 0
1
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Trying to understand pixel value.
I am trying to understand pixel value, and trying to learn to alter it. But things act weird in matlab. Correct me if I am wrong...
6 years 前 | 1 个回答 | 0
1
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How do I plot six different matrices?
I have 6 different matrixes, 22x1 each one. When I plot them I get this: plot(x1,y1,'o',x2, y2,'o', x3, y3,'o') %%Using this co...
7 years 前 | 4 个回答 | 0
4
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I get this error:"This system does not seem to be linear."
When I try this code for simple pendulum, I get results: syms pt(t) th(t) m=1; l=0.5; g=9.81; e1= diff(th)*(m*l^2)==pt; e2= ...
7 years 前 | 2 个回答 | 0
2
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Can't understand why does it say "The expression to the left of the equals sign is not a valid target for an assignment."
1- function dydt = lagrang(~, y) 2- syms m1 m2 m3 l1 l2 l3 g 3- dydt = zeros(6,5,4,3,2,1); 4- m1=1; m2=1; m3=1; l1=1; l2=...
7 years 前 | 3 个回答 | 0
3
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Ode45 I get wrong results.
function dydt = idn (t, y) dydt = zeros(2,1); dydt(1)=y(2); dydt(2)=-((9.81*sin(y(1)))/0.5); dydt = [0.78 0]; [t1,y1] =...
7 years 前 | 1 个回答 | 0
1
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How to solve this equations?
These are hamoltionian ways of triple pendulum. I am very new to matlab and, I know little to nothing. I need a direction t...
7 years 前 | 1 个回答 | 0
