marcus peixoto
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rounding down using floor
so im using: floor(10^decimal*(total/AVERAGE_COUNT))/10^decimal; where: decimal = 4, AVERAGE_COUNT = 9, total = 8.9289 this ...
4 years 前 | 1 个回答 | 0
Followers: 0 Following: 0
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4 years 前 | 1 个回答 | 0