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MRINAL BHAUMIK


Last seen: 5 months 前 |  自 2021 起处于活动状态

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Finding the indices of duplicate values in one array
A=[ 1 1 2 3 5 6 7 6] B = A'./A B = B-diag(diag(B)) [pos1 pos2]=find(B==1) o/p pos1 = 2 1 8 6

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Replace previous values with NaN
I have a vector with some numbers. if any of the number comes NaN then all the number before NaN will be NaN. ex. A=[1 2 3 4 Na...

3 years 前 | 1 个回答 | 0

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