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How do i use boundary conditions to find variables in an equation
Hi all. I am trying to find 4 variables which are c1, c2, c3, c4 in my equation using 4 boundary conditions. The value of lambda...
6 years 前 | 1 个回答 | 0
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integration using two variables
I have two expressions for variables a and x M = (-150 + 20.556*x - ((1/2)*(x-10)^2 - (1/60)*(x-10)^3))*heaviside(20-x) + (5.5...
6 years 前 | 1 个回答 | 0
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how to say 2 variables are equal and solve for one variable? I have two eqations having variables a and x. After integrating the equation, i get the solution 'y' in terms of 'a' and 'x'. Now I wand to differentiate 'y' w.r.t. 'a' for a=x. How to do?
syms x a Mx = (-150 + 20.556*x - ((1/2)*(x-10)^2 - (1/60)*(x-10)^3))*heaviside(20-x) + (5.556*x+(250/3))*heaviside(x-20); delM...
6 years 前 | 1 个回答 | 0
