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invert the function s = L(t) to solve for t.
syms t; x(t)= sin(3*t^2)*(12*t + (10*13^(1/2))/13); y(t)= t*(6*13^(1/2)*t + 5); z(t)= cos(3*t^2)*(12*t + (10*13^(1/2))/13); ...
5 years 前 | 1 个回答 | 0
1
个回答提问
arc length parametrization help me
syms t; x(t) = sin(3*t^2)*(12*t + (10*13^(1/2))/13); y(t) = t*(6*13^(1/2)*t + 5); z(t) = cos(3*t^2)*(12*t + (10*13^(1/2))/13)...
5 years 前 | 1 个回答 | 0
1
个回答提问
nothing appears with this code
syms t; x(t) = sin(3*t^2)*(12*t + (10*13^(1/2))/13); y(t) = t*(6*13^(1/2)*t + 5); z(t) = cos(3*t^2)*(12*t + (10*13^(1/2))/13)...
5 years 前 | 1 个回答 | 0
