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making a rotation matrix
{ clc b = [cos((angle/180)*pi) -sin((angle/180)*pi);sin((angle/180)*pi) cos((angle/180)*pi)]; for i = 1:1:size(nr_out,1) a ...
12 years 前 | 1 个回答 | 0
1
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making a 341x341 matrix from a 465124x1 matrix.
Hello everybody, I have a matrix that is 465124x1. From this matrix I want every 341 values put in another matrix. so the va...
12 years 前 | 2 个回答 | 0
2
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plot Bethe-Bloch equation
Dear people, For a project I have to plot the Bethe-Bloch equation. That is this equation: dedx = (-K*z^2*Z)/(A*beta2)*(0.5*l...
12 years 前 | 1 个回答 | 0
1
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non zero elements above 70 and below -70 zero
hello people, In a matrix I want that all non zero elements above 70 and below -70 is zero. How do I do that ? Thank y...
13 years 前 | 4 个回答 | 0
4
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how to speed up this nestled for loop
Okay thank you for your respons! But this is not what i want. i have matrix M. That matrix has 6 rows and 235238 columns. Now ...
how to speed up this nestled for loop
Okay thank you for your respons! But this is not what i want. i have matrix M. That matrix has 6 rows and 235238 columns. Now ...
13 years 前 | 0
已回答
how to speed up this nestled for loop
Thank Andrei Bobrov for your fast answer. But this yields a 235238 by 3 matrix and it needs to be a 235238 by 6 matrix. Anywa...
how to speed up this nestled for loop
Thank Andrei Bobrov for your fast answer. But this yields a 235238 by 3 matrix and it needs to be a 235238 by 6 matrix. Anywa...
13 years 前 | 0
提问
how to speed up this nestled for loop
Hi everybody, I need to make this code faster: for i=1:n1*n2*n3; x1 = M(i,1); y1 = M(i,2); ex1 = M(...
13 years 前 | 3 个回答 | 0