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Naveen Gehlot


Last seen: 4 years 前 自 2020 起处于活动状态

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统计学

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Solving 2nd part of minimax question
function [mmr, mmm]= minimax (A) mmr = [max(A,[],2)- min(A,[],2)]'; mmm = max(A,[],'all')-min(A,[],'all'); OUTPUT mmr =...

4 years 前 | 0