Apurva Suman
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Solving partial differential equation of second in two variables
how to solve this partial differential equation? here u is a function of r and theta, I know the boundary conditions but how to ...
2 years 前 | 1 个回答 | 0
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I'm getting error as "First argument must be scalar" while finding roots of a 8 degree poynomial
root([2*A*B*K^2 - B^2*K^2 - A^2*K^2, - 4*A*B*K^2*R + 2*B^2*K^2*R + 2*A^2*K^2*R + 2*B*C*K^2 - 2*A*C*K^2, - 2*B*C*K^2*R + 2*A*C*K^...
3 years 前 | 1 个回答 | 0
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I'm getting equation in very long form, there are big numbers that are left undivided, how do i get them in a simpler term?
root(z^5 - (110641566850204558710322674623436416308237*z^4)/56273926637118816003144160544915628125000 + (23897303543479682720741...
3 years 前 | 1 个回答 | 0
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How to get the equation inside that of root(function,z) equation ,i.e the function only
root(z^4 - (190266216202962831605969987684001433013625*z^3)/142934430860719287430314339936263093557948 + (1101852793399817336417...
3 years 前 | 2 个回答 | 0