charles alexander
Followers: 0 Following: 0
Provide your first answer ever to someone else's question
Awarded to charles alexander on 21 Nov 2020
Answer 1 question that was unanswered for more than 30 days
Awarded to charles alexander on 21 Nov 2020
Feeds
已回答
variance-covariance matrix EWMA
it is simple, the matrix is distributive. a(bk)=ab(K). the variable k is 14. i suggest this matrix; {a1n a2n a10} by ...
variance-covariance matrix EWMA
it is simple, the matrix is distributive. a(bk)=ab(K). the variable k is 14. i suggest this matrix; {a1n a2n a10} by ...
4 years 前 | 0
您也可以从以下列表中选择网站：
美洲
- América Latina (Español)
- Canada (English)
- United States (English)
欧洲
- Belgium (English)
- Denmark (English)
- Deutschland (Deutsch)
- España (Español)
- Finland (English)
- France (Français)
- Ireland (English)
- Italia (Italiano)
- Luxembourg (English)
- Netherlands (English)
- Norway (English)
- Österreich (Deutsch)
- Portugal (English)
- Sweden (English)
- Switzerland
- United Kingdom(English)
亚太
- Australia (English)
- India (English)
- New Zealand (English)
- 中国
- 日本Japanese (日本語)
- 한국Korean (한국어)