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Maimoona Asad
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Hi, i am trying again and again but my plot is empty.
clc clear all close all clc clear all close all tt=100:100:200; L=12; % IRS element=10; lambda=0.06; l=lambda/2; Sig...
2 years 前 | 1 个回答 | 0
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Hi everyone, I have a vector of 5 columns, x=[1 2 3 4 5]; i want to create all possible combinations of first element with the other remaining.
Hi everyone, I have a vector of 5 columns, x=[1 2 3 4 5]; i want to create all possible combinations of first element with the o...
2 years 前 | 1 个回答 | 0
1
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how to save number of organization for each cluster in k mean clustering.
i am making 4 clusters using k mean clustering. i want to get and save the indexes of the data which are a part of each cluster ...
2 years 前 | 1 个回答 | 0
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I want to make 4 clusters using k mean clustering and for each of the 4 clusters i want to set centroid initially and then accordingly make the cluster. how can I.
X3=[-6.189; -3.251; 2.926; 6.534; 10.79; 5.203; -4.465; 1.42; -8.66; -0.8748; 6.534 ; 11.251] ; Y3=[ 1.393; 10.42; 6.639; 5.821...
2 years 前 | 1 个回答 | 0
1
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I want to make 4 clusters using k mean clustering and for each of the 4 clusters i want to set centroid initially and then accordingly make the cluster. how can I.
I want to make 4 clusters using k mean clustering and for each of the 4 clusters i want to set centroid initially and then accor...
2 years 前 | 3 个回答 | 0
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i want to store a 100 x 100 matrix in hi_i for each iteration of irs1 and irs 2 when my sij1*sij2' is of 100x100 multiplied by a scalar in h_i.
L=12; % IRS element=10; lambda=0.06; l=lambda/2; %% channel between IRS and IRS rr=11; for irs1 = 1:(L-1) % IRS1 ...
2 years 前 | 1 个回答 | 0
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i want to give de_e a shape of matrix of order 100x400 how can I?. I want output to be in order of j1xj2 rows and k1xk2 rows.Thanks
for iteration = 1:length(N) % Iterations nn=N(n); for irs1 = 1:(L-1) % IRS1 to be multip...
2 years 前 | 1 个回答 | 0
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how can i compute x_e (10x10) for first iteration of n and x_e (10x20) for second iteration of n?
clc clear all close all L=12; % IRS element=10; lambda=0.06; l=lambda/2; a_db=-46; alpha=db2pow(a_db); K=4; radius=15...
2 years 前 | 0 个回答 | 0
0
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How to solve too many arguments error in the bold part
clc clear all close all L=12; % IRS element=10; lambda=0.06; l=lambda/2; K=4; radius=15; X0=0; % x-coordinate of Ce...
2 years 前 | 1 个回答 | 0
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How can i store the values for each of the 10 iterations of N. i want to store each and every value of the loop.
L=2; element=10; lambda=1.3; l=lambda/2; X3=[-7.655; 6.534]; Y3=[1.393;-7.03]; p=0; %% loop for the elements of irs for ...
2 years 前 | 1 个回答 | 0
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ToHow can we subtract two graphs using a command...?
I ploted two rf plots. But i want to subtract these two graphs how can I do this..?
2 years 前 | 1 个回答 | 0
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I am facing problem regarding storage of values for d() using for loop which is of 100x100 size for each iteration of a and k.
clc clear all close all %% Cell generation alpha=4; % pth loss exponent p=-30; % power= 10db p_lin=db2pow(p); radi...
2 years 前 | 1 个回答 | 0
1
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i want to ask how can i store the value of d_eb for each iteration of loop
I am stuck in one thing if you could help please. how can i store deb mentoined by bold letters in the end for each iteration. ...
2 years 前 | 2 个回答 | 0
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i want to store the values of bold part for each iteration of i.
for i=1:3 for j=1:10 for k=1:10 x3(j,k)=X3(i)+p; y3(j,k)=Y3(i); p=k*l; ...
2 years 前 | 1 个回答 | 0