Ashish Kumar
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Awarded to Ashish Kumar on 10 Feb 2022
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Awarded to Ashish Kumar on 10 Feb 2022
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Finite potential well transcendental graph
clear all; e=1.6*10^-19; % eV to Joules V=10*e; L=1.8*10^(-9)/2; m=9.11e-31; h_bar=(6.63e-34)/(2*pi); a=(sqrt(2*m)*...
Finite potential well transcendental graph
clear all; e=1.6*10^-19; % eV to Joules V=10*e; L=1.8*10^(-9)/2; m=9.11e-31; h_bar=(6.63e-34)/(2*pi); a=(sqrt(2*m)*...
2 years 前 | 0
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