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Onesimus Hewett


Last seen: 9 months 前 |  自 2023 起处于活动状态

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How to apply the same operation to an ever increasing number of columns?
The easiest method is to use a for loop. C = zeros(20, 7); for i = 1:7 C(:, i) = B(:, 1:i)*A(1:i)'; end C

9 months 前 | 1