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Yanni


Last seen: 3 months 前 |  自 2022 起处于活动状态

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MATLAB

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How to use iteration and error for crank nicolson type to converge spatial and temporal discretization?
I'm using iteration and error for spatial discretization and temporal discretization respectively. I want apply iteration and er...

12 months 前 | 1 个回答 | 0

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提问


How to obtain convergence of the curve to my boundary condtion?
I want a curve in each 'j'th iteration. But, I didn't get convergence of the curve to plot each 'j'th iterations between limit 1...

1 year 前 | 1 个回答 | 0

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提问


How to stop time loop when steady state is reached?
I'm using unsteady case. so, it will reach a steady state at a certain time level. I fixed time at 'j'th column wise and it ran ...

1 year 前 | 1 个回答 | 0

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What is the steady state criteria in crank nicolson scheme, especially impilicit finite difference method? and How to stop time level when steady state is reached?
I'm dealing with unsteady case in my code. so, the CN term updated in each time step and it ran upto final time (tmax=100). but ...

1 year 前 | 1 个回答 | 0

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How to use indices in A matrix while conditonal and for loop condtion?
How to use indices in LHS of A matrix while using for and if, esleif and else condtions? clc clear all m=5;n=7; A=zeros(m,m)...

1 year 前 | 2 个回答 | 0

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How to change diagonal, subdiagonal and superdiagonal values with respect time while using loop and conditional statement?
xmax=1; ymax=7; m=20; n=29; dx=xmax/m; dy=ymax/n; dt=0.2; UOLD=zeros(m,n);VOLD=zeros(m,n); A=zeros([1,m]); B=A; C=A; whi...

1 year 前 | 2 个回答 | 0

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How to describe right hand side of energy equation in tridiagonal system? Didn't get right hand side values of tridiagonal matrix.
xmax=1; ymax=20; dx=0.05; dy=0.25; dt=0.02; m=xmax/dx; n=ymax/dy; U=zeros(m,n); V=zeros(m,n); for j =1:n D(i)=-U(i,j)*...

1 year 前 | 1 个回答 | 0

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There is a mistake while using condtional and for loop condtion.i got the value zero only. but i want values and here, A is subdiagonal, B is diagonal and C is superdiagonal.
xmax=1; ymax=20; dx=0.05; dy=0.25; dt=0.02;m=xmax/dx; n=ymax/dy; UOLD=zeros(m,n); VOLD=zeros(m,n); for j=1:n if i==2:m...

1 year 前 | 1 个回答 | 0

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提问


here, i couldn't get the A,B,C values while using if, elseif conditions. how to get values while using conditional statement?
dx=0.05; dy=0.25; dt=0.2; for j=1:n if i==2:m C(i)=V(i,j)*dt/4*dy-dt/2*(dy)^2; elseif i==1:m-1 A(i)...

1 year 前 | 1 个回答 | 0

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