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Hozifa


Last seen: 2 months 前 |  自 2022 起处于活动状态

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统计学

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Find average average value of data
Hello, I have this code, I want it to do a single run, in a way that it the code exucte the value for each row independently. ...

2 months 前 | 1 个回答 | 0

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fitting data to a decaying exponential distribution
Hello there, I have this data (attached) and i dont know how to fit it to a decaying exponential distribution, if it possibl...

1 year 前 | 1 个回答 | 0

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How to fit the cdf to a function?
Hi there, I want my code to give the exponential fit as a function of the x-axis values, in my code, the fit function depends o...

1 year 前 | 1 个回答 | 1

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How to generalise my code?
Hello everybody, I have written a code, it works fine as long as I am taking each group of XX alone, I need to find away to ru...

2 years 前 | 1 个回答 | 0

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Matlab code modification request
Hi there, I have this code, the code takes 10 rows at a time from the XX matrix, and then does the work, then it takes the nex...

2 years 前 | 0 个回答 | 0

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Poisson distribution and discrete distribution
Hello guys, I have two set of data, the first one I have to fit it to a Poisson distribution while the second one I have to fi...

2 years 前 | 1 个回答 | 0

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How I can add an exponential fit to my cdfplot?
Hi there, I have data to be used in a cdfplot as shown below, if I want to add on the plot an exponential fit to the data, what...

2 years 前 | 1 个回答 | 0

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I want to do exponential fitting for power decaying with time
Hi there, I have this matrix (first cloumn is time while the second column is received power), I want to do exponentially fitt...

2 years 前 | 3 个回答 | 0

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Plot polar plot for AOA
Hi there, I have angle of arrival results (rays coming from different angles with different power), the results contain the az...

2 years 前 | 1 个回答 | 0

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How can I segment a matrix based on the difference between a column's elements of the matrix?
I have a matrix (X), I want it to be segmented such that for each segment, the difference between successive first column entrie...

2 years 前 | 1 个回答 | 0

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