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Welcome I have a CF equation that performs a three-dimensional summation process and gives a two-dimensional result I did this process using (For Loops) in MATLAB. I want to c
clc xm(:,:,1)= [1 2 3 4;2 3 4 5;3 4 5 6;4 5 6 7 ] xm(:,:,2)= [2 3 4 5;3 4 5 6;4 5 6 7;5 6 7 8] tic [cf] =coherence_factor(...
2 years 前 | 1 个回答 | 0
1
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Hello, how can I calculate the row and column by inserting a 3D matrix using this equation,, so that the input 3D matrix and output 2D matrix
clc clear all close all xm= [5 5 5 5;5 -4 -3 -2;5 -1 0 1;5 2 3 4] n=length(xm); [cf] =coherence_factor(xm,n) function ...
2 years 前 | 1 个回答 | 0
1
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Hello, how can I calculate the row and column by inserting a 3D matrix using this equation
clc clear all close all xm= [5 5 5 5;5 -4 -3 -2;5 -1 0 1;5 2 3 4] n=length(xm); [cf] =coherence_factor(xm,n) function ...
2 years 前 | 0 个回答 | 0
0
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Hello, how can I do a (for loop) for this equation to find more than one value of the CF ? Specifically, I mean more than one value for (xm)
function [CF]= Coherence_Factor(xm,N); CF = ((abs (sum(xm))).^2) / (N* sum(abs(xm.^2))) end %Function call window xm= [-1:...
3 years 前 | 2 个回答 | 0
2
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Hello, how can I do a (loop) for this equation to find more than one value of the CF ? Specifically, I mean more than one value for (xm)
function [CF]= Coherence_Factor(xm,N); CF = ((abs (sum(xm))).^2) / (N* sum(abs(xm.^2))) end
3 years 前 | 1 个回答 | 0
1
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Hello, I would like to convert this mathematical equation into MATLAB with function code.
3 years 前 | 0 个回答 | 0
0
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Hello, I would like to convert this mathematical equation into MATLAB code.
3 years 前 | 1 个回答 | 0
