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inverser la matrice tri-diagonale
a=3*h -2; b=1; c=1; A=diag(a*ones(1,N)) + diag(b*ones(1,N-1),1)+ diag(c*ones(1,N-1),-1) inverser A
1 year 前 | 1 个回答 | 0
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problem onn numerical solution
= 0.3; % Rayon de lissage dx=0.3; N =floor(1/dx); x =0:dx:(pi/sqrt(3)); % Positions des particules dt = 1/4; t = 0:dt:1; M...
1 year 前 | 1 个回答 | 0
