Feeds
已回答
Recursive relation
If I assume y(x)= sum(xk y^k), then dy/dx = k sum(xk * y^{k-1}) and y²(x) = sum ( sum (y(k-l)*y(l))) * x^k, the first sum being...
    
  
Recursive relation
If I assume y(x)= sum(xk y^k), then dy/dx = k sum(xk * y^{k-1}) and y²(x) = sum ( sum (y(k-l)*y(l))) * x^k, the first sum being...
13 years 前 | 0
提问
Recursive relation
Hi, I'ld like to plot the solution of dy/dx - y² = -exp(-x) on MATLAB. I assumed the solution was in the form of a Taylor se...
13 years 前 | 4 个回答 | 0
