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Jean Araujo


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Write a function called one_per_n that returns the smallest positive integer n for which the sum 1 + 1/2 + 1/3 + … + 1/n , is greater than or equal to x where x is the input argument. Limit the maximum number n of terms in the sum to 10,000 .
function out = one_per_n(x) total=0; n = 1; while total < x total = (total+1/n); n = n+1; end if n-1 > 1...

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