Feeds
已回答
Using the ellipse graph.
L=0.5; e=0.5; phi0=0; phi=linspace(0,2*pi); rho=L*(1-e^2)./(1-e*cos(phi-phi0)); polar(phi,rho)
Using the ellipse graph.
L=0.5; e=0.5; phi0=0; phi=linspace(0,2*pi); rho=L*(1-e^2)./(1-e*cos(phi-phi0)); polar(phi,rho)
6 years 前 | 0
