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Holder exponent time consuming
%Calculating standard Deviations for HE %Calculating holder exponent values HE=zeros(131072,2); HE(:,1) = estimOSC1DH...
9 years 前 | 0 个回答 | 0
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个回答提问
Subscript indices must either be real positive integers or logicals.
for i=1:21 H=linspace(0,4,21)'; Hloop=H(i); temp=find(c(:,1)>0 & HEc(:,1) > 0 & abs(nf(:,1).*ng(:,1))>Hloop)...
9 years 前 | 3 个回答 | 0
