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How to access the previous value during an ODE - Acceleration
I have a 2nd order ODE to solve in MATLAB: ( (a + f(t))·d²x/dt² + (b/2 + k(t))·dx/dt ) · dx/dt - g(t) = 0 Initial co...
9 years 前 | 0 个回答 | 0
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How do I solve this 2nd order ODE with time-dependent parameters?
2nd ODE to solve dx/dt*(a + f(t))* d2x/dt2 + 0.5*b*(dx/dt)^2 + k(t)*(dx/dt)^2 - g(t) = 0 Boundary condition: dx/dt(0) =...
9 years 前 | 2 个回答 | 1
2
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How could I solve this 2nd order ODE with ode45?
2nd ODE to solve dx/dt*(a + f(t))* d2x/dt2 + 0.5*b*(dx/dt)^2 + k(t)*(dx/dt)^2 - g(t) = 0 Boundary condition: dx/dt(0) =...
9 years 前 | 1 个回答 | 0
