uistack
对 UI 组件的视图堆叠重新排序
说明
示例
创建一个 UI 图窗，其中包含一个按钮和一个仪表。由于先创建按钮后创建仪表，因此仪表会出现在顶层并覆盖按钮。
fig = uifigure; btn = uibutton(fig,"Text","Go","Position",[148 148 25 25]); g = uigauge(fig);
通过将按钮移至层叠的顶部，将按钮置于顶层。
uistack(btn,"top");
创建一个 UI 图窗，其中包含五个具有不同标题和背景颜色的重叠面板。
fig = uifigure; a = uipanel(fig,"Title","A","BackgroundColor","white","Position",[200 200 170 150]); b = uipanel(fig,"Title","B","BackgroundColor","cyan","Position",[100 170 170 150]); c = uipanel(fig,"Title","C","BackgroundColor","green","Position",[50 90 170 150]); d = uipanel(fig,"Title","D","BackgroundColor","yellow","Position",[140 140 170 150]); e = uipanel(fig,"Title","E","BackgroundColor","magenta","Position",[170 110 170 150]);
在 UI 图窗中列出子级。
fig.Children
ans = 5×1 Panel array: Panel (E) Panel (D) Panel (C) Panel (B) Panel (A)
通过将面板 a 和 c 在层叠中相对于当前位置上移一层，对面板重新排序。
comp = [a c]; uistack(comp)
再次列出子级项。更改面板的层叠顺序也会更改 UI 图窗中子级项的顺序。
fig.Children
ans = 5×1 Panel array: Panel (E) Panel (C) Panel (D) Panel (A) Panel (B)
创建一个 UI 图窗，它包含具有两个顶层节点的树，其中每个节点有两个子节点。
fig = uifigure; t = uitree(fig,"Position",[20 20 150 150]); category1 = uitreenode(t,"Text","Vegetables"); category2 = uitreenode(t,"Text","Fruits"); n1 = uitreenode(category1,"Text","Cucumber"); n2 = uitreenode(category1,"Text","Carrot"); n3 = uitreenode(category2,"Text","Apple"); n4 = uitreenode(category2,"Text","Banana");
展开树中的所有节点。
expand(t)
将 Fruits 节点移至层叠的顶部。该节点会相对于共享一个父节点的所有其他节点重新排序。以下命令将 Fruits 节点及其所有子节点移至 Vegetables 节点上方。
uistack(category2,"top")
重新排列 Fruits 节点的子节点。将 Apple 节点向下移动一层，移至 Banana 节点下方。
uistack(n3,"down",1)
创建一个包含选项卡组（其中包含五个选项卡）的 UI 图窗。
fig = uifigure; tg = uitabgroup(fig,"Position",[20 20 450 300]); t1 = uitab(tg,"Title","Survey Questions"); t2 = uitab(tg,"Title","Demographic"); t3 = uitab(tg,"Title","Participants"); t4 = uitab(tg,"Title","Data"); t5 = uitab(tg,"Title","Plot");
将 Data 选项卡移至层叠的底部。该选项卡显示在最右侧。
uistack(t4,"bottom")
将 Survey Questions 选项卡向右移动两层。
uistack(t1,"down",2)
