Generate vectors of values for the number of successes and probability of success in each trial.
P = 0.1:0.2:0.9;
R = 1:5;
For each pair of elements in P and R, calculate the mean and variance for the corresponding negative binomial distribution.
[M,V] = nbinstat(R,P)
M = 1×5
9.0000 4.6667 3.0000 1.7143 0.5556
V = 1×5
90.0000 15.5556 6.0000 2.4490 0.6173
Each pair of elements in the vectors M and V contains the mean and variance for the negative binomial distributions corresponding to the pairs of elements at the same positions in P and R.
Number of successes, specified as a positive scalar value or an array of positive
scalar values. The elements of R can be noninteger values. If both
R and P are arrays, they must be the same
size. If either R or P is a scalar, then
nbinstat expands the scalar argument into a constant array of
the same size as the other argument.
Example: [3 1 7]
Data Types: single | double
Probability of success in a single trial, specified as a positive scalar value or an
array of positive scalar values. The elements of P must be between
0 and 1. If both P and R are arrays, they must
be the same size. If either P or R is a
scalar, then nbinstat expands the scalar argument into a
constant array of the same size as the other argument.
Mean for the negative binomial distribution, returned as a numeric scalar or an
array of numeric scalars. M is the same size as
R and P. Each element in
M is the mean of the negative binomial distribution specified by
the corresponding elements in R and P. For
more information, see Mean.
Data Types: single | double
Variance for the negative binomial distribution, returned as a numeric scalar or an
array of numeric scalars. V is the same size as
R and P. Each element in
V is the variance of the negative binomial distribution specified
by the corresponding elements in R and P. For
more information, see Variance.
