making new code by calling 3 different RANDOM variables
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[EDIT: 20110627 13:09 CDT - reformat - WDR]
This function will generate a normal distribution conditional by bounds:
i have used above code 3 times and made 3 random variables c, fi, G. now i want to calculate qult.
this is my code :for getting distribution of qult i need to produce 3 different random variables (c, fi, G) by above code and call them in a new code to get answer. how should i use c, fi, G that i produced and call them in a loop to compute qult.
this is my code for qult:
B=1000;L=2000;Sc=1.1;Sq=1.1;Sgama=.8;
nsamples=10000;
for i=1:nsamples
C=C(1,i);
G=G(1,i);
fi=fi(1,i);
Nq=tan((pi/4)+(pi*fi/360))*tan((pi/4)+(pi*fi/360))*2.718^(pi*tan(fi*pi/180));
Nc=(Nq-1)*cot(fi*pi/180);
Ngama=2*(Nq+1)*tan(fi*pi/180);
qult(i)=(C*Nc*Sc)+(384*Nq*Sq)+(980*Ngama*Sgama);
end
8 个评论
Jan
2011-6-27
Please use the "{} Code" button to format your code such that it is more readable.
Andrew Newell
2011-6-27
What is qult?
milad babaei
2011-6-28
Krishna Kumar
2011-6-28
how can you use C=C(l,i).Wont that return an error.
Better use different values for the purpose. The UBC or Qult formula uses one value of C Nc,etc, so you should be using C(l,i).
Further, what is the problem you are facing with this?
milad babaei
2011-6-28
Krishna Kumar
2011-6-28
you still havent elaborated on your problem. Also why run two threads?
milad babaei
2011-6-28
Krishna Kumar
2011-6-28
Refer to my earlier comment here. if a matrix X is 5x5, and you do sth like this
X=X(3,1);
Now X is a scalar. The next time if you run
X(4,1), error is generated, since X is 1x1.
You need to use separate variables for the matrix of random numbers and the particular random num taken in loop.
采纳的回答
Walter Roberson
2011-6-28
On the first iteration through the loop, your statements
C=C(1,i);
G=G(1,i);
fi=fi(1,i);
are equivalent to
C=C(1,1);
G=G(1,1);
fi=fi(1,1);
That is, you take a single value out of the array C and you replace the entire array C with that single value; likewise for G and fi. So after the first iteration, C and G and fi each only have one element left.
What you should do is rename your C, G, and fi variables so that you are not storing over your C, G, and fi arrays.
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2011-6-27
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