How do I index correctly from my questdlg command to my if statement? I am trying to direct the user into different code based on their questdlg responses. I have many more in this code but I am stuck HELP!

Question

Sean 2013-12-5

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此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/108836-how-do-i-index-correctly-from-my-questdlg-command-to-my-if-statement-i-am-trying-to-direct-the-user

评论： Sean 2013-12-5

quest = 'What type of rod are you using?';
qtitle = 'Axial load problem';
a = {'Circular', 'Rectangular'};
resp=questdlg(quest,qtitle,a{1},a{2},a{1}); 
h=msgbox(sprintf('You selected %s',resp));
respa = str2num('resp');
waitfor(h);
if respa == 1
% create a user prompted space to calculate the axial load problem for a
% circular rod
dlg_prompts = {'Axial load','Radius','Inner Radius',...
    'Length','Young''s Modulus E'};
dlg_title = 'Axial Load';
dlg_defaults = {'0','0','0','0','0'};
opts.Resize = 'on';  % a structure
dlg_ans = inputdlg(dlg_prompts,dlg_title,1,dlg_defaults,opts);
P = str2double(dlg_ans(1));
r = str2double(dlg_ans(2));
ir = str2double(dlg_ans(3));
L = str2double(dlg_ans(4));
E = str2double(dlg_ans(5));
else
% create a user prompted space to calculate the axial load problem for a
% rectangular rod
dlg_prompts = {'Axial load','Base','Height','Inner Base','Inner Height',...
'Length','Young''s Modulus E'};
dlg_title = 'Axial Load';
dlg_defaults = {'0','0','0','0','0','0','0'};
opts.Resize = 'on';  % a structure
dlg_ans = inputdlg(dlg_prompts,dlg_title,1,dlg_defaults,opts);
P = str2double(dlg_ans(1));
b = str2double(dlg_ans(2));
h = str2double(dlg_ans(3));
ib = str2double(dlg_ans(4));
ih = str2double(dlg_ans(5));
L = str2double(dlg_ans(6));
E = str2double(dlg_ans(7));
end%if

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Answer 1

Kelly Kearney 2013-12-5

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Since you know the possible strings in advance, a switch/case block might be better:

 quest = 'What type of rod are you using?';
 qtitle = 'Axial load problem';
 a = {'Circular', 'Rectangular'};
 resp=questdlg(quest,qtitle,a{1},a{2},a{1});
 switch resp
     case 'Circular'
         % circular code here   
     case 'Rectangular'
         % rect code here
end