Find the maximum value and its location from a matrix using two nested loops

29 次查看(过去 30 天)
Hi,
Right now I have this matrix K
K =
-3 -8 6 -3 -8 6 9 24 -18
-5 10 -9 -5 10 -9 15 -30 27
8 4 9 8 4 9 -24 -12 -27
-9 -24 18 12 32 -24 3 8 -6
-15 30 -27 20 -40 36 5 -10 9
24 12 27 -32 -16 -36 -8 -4 -9
9 24 -18 -15 -40 30 0 0 0
15 -30 27 -25 50 -45 0 0 0
-24 -12 -27 40 20 45 0 0 0
I wonder how I can use two nested loops to find the maximum number and its location from this matrix.
It would be great if anyone can help me with this
Thank you very much :)

采纳的回答

sixwwwwww
sixwwwwww 2013-12-8
编辑:sixwwwwww 2013-12-8
you can do it as follow:
MaxValue = -Inf;
row = 0;
column = 0;
for i = 1:size(K, 1)
for j = 1:size(K, 2)
if K(i, j) > MaxValue
MaxValue = K(i, j);
row = i;
column = j;
end
end
end
  6 个评论
Image Analyst
Image Analyst 2013-12-8
But you didn't ask for other ways - you rigidly specified the way. The other, more MATLAB-ish way would be to use the max() function. Look at the two arguments it returns. You might also find ind2sub() helpful,

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更多回答(1 个)

Khalid Mojallid
Khalid Mojallid 2019-3-26
MaxValue = -Inf;
row = 0;
column = 0;
for i = 1:size(K, 1)
for j = 1:size(K, 2)
if K(i, j) > MaxValue
MaxValue = K(i, j);
row = i;
column = j;
end
end
end

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