Find the maximum value and its location from a matrix using two nested loops

13 次查看（过去 30 天）

显示更早的评论

Kantosa 2013-12-8

1
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/109104-find-the-maximum-value-and-its-location-from-a-matrix-using-two-nested-loops

编辑： Alexandra Vaupotic 2021-2-8

采纳的回答： sixwwwwww

在 MATLAB Online 中打开

Hi,

Right now I have this matrix K

K =
      -3    -8     6    -3    -8     6     9    24   -18
      -5    10    -9    -5    10    -9    15   -30    27
       8     4     9     8     4     9   -24   -12   -27
      -9   -24    18    12    32   -24     3     8    -6
     -15    30   -27    20   -40    36     5   -10     9
      24    12    27   -32   -16   -36    -8    -4    -9
       9    24   -18   -15   -40    30     0     0     0
      15   -30    27   -25    50   -45     0     0     0
     -24   -12   -27    40    20    45     0     0     0

I wonder how I can use two nested loops to find the maximum number and its location from this matrix.

It would be great if anyone can help me with this

Thank you very much :)

1 个评论
显示 -1更早的评论隐藏 -1更早的评论

sixwwwwww 2013-12-8

Is it homework?

请先登录，再进行评论。

请先登录，再回答此问题。

采纳的回答

sixwwwwww 2013-12-8

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/109104-find-the-maximum-value-and-its-location-from-a-matrix-using-two-nested-loops#answer_117740

编辑：sixwwwwww 2013-12-8

在 MATLAB Online 中打开

you can do it as follow:

 MaxValue = -Inf;
 row = 0;
 column = 0;
 for i = 1:size(K, 1)
     for j = 1:size(K, 2)
         if K(i, j) > MaxValue
             MaxValue = K(i, j);
             row = i;
             column = j;
         end
     end
 end

But you didn't ask for other ways - you rigidly specified the way. The other, more MATLAB-ish way would be to use the max() function. Look at the two arguments it returns. You might also find ind2sub() helpful,