Read files in zip file without unzipping

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Etienne Coetzee
Etienne Coetzee 2011-7-5
评论： Mark Gugliuzza 2023-3-21
Hi there
I have a zip file with about 100 binary files in. I have a routine to read the files into matlab variables. Is there a way that I can read the files directly without unpacking the zip file?
Thanks in advance.
Etienne
  1 个评论
Jan
Jan 2011-7-6
What do you want to do with a zipped variable? Do you want to unzip one of the files only?

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回答（4 个）

Bob Hamans
Bob Hamans 2011-7-6
Hi Etienne. I don't know if I understand your question but you just want to list the zip file contents without unzipping? The following code does just that:
function filelist = listzipcontents(zipFilename)
% Create a Java file of the ZIP filename.
zipJavaFile = java.io.File(zipFilename);
% Create a Java ZipFile and validate it.
zipFile = org.apache.tools.zip.ZipFile(zipJavaFile);
% Extract the entries from the ZipFile.
entries = zipFile.getEntries;
% Initialize the file list.
filelist={};
% Loop through the entries and add to the file list.
while entries.hasMoreElements
filelist = cat(1,filelist,char(entries.nextElement));
end
end
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Lars Janssen
Lars Janssen 2021-3-1
For those using the code snippet above, please add:
zipFile.close
This will "unlock" the java file again. After having some trouble deleting the zip file I found this missing piece of code here:Extracting specific file from zip in matlab - Stack Overflow.
Mark Gugliuzza
Mark Gugliuzza 2023-3-21
Does anyone know if it is possible to perform this recursively? I have zips within zips that I need to read all the file names out of?

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Etienne Coetzee
Etienne Coetzee 2011-7-6
Ok, thanks Robert. I will log it as an enhancement.
Robert Cumming
Robert Cumming 2011-7-6
have you seen this thread - you could try what it suggests in your own copy of unzip.m - or send an enhancement request to Mathworks.
Its actually quite easy to update the m file(s):
1. Change the number of accepted input arguments to 3.
2. Handle the third input agument (say a cell array of requested files) or set to default (empty cell array)
3. Pass the 3rd argument into the private function extractArchive
4. In the private function do a strcmp on the entryName and your cell array of requested file(s) - if match found extract, if not skip to next (use continue in the while loop)
Brunno Machado de Campos
Hi, If anyone is until interested, for zip, on Windows (where I tested):
a = fopen('ZIPFILENAME.zip','r');
c2 = fread(a,'uint8=>uint8');
zipname = char(c2(31:31+c2(27)-1));
zipname = strcat(zipname')

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