Pushbotton which can not be controled with a 'Pause' command.

Question

Reeki 2014-1-26

0
链接

此问题的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/113750-pushbotton-which-can-not-be-controled-with-a-pause-command

评论： Reeki 2014-1-26

Hi!

I hope someone can help me with this. I've made a GUI and what it does is: when the user press button 1 it ask's the user to choose a wav file. If they press button 2, there is a denoiser which removes some ambient noise included in the files. And then if they press button 3, it starts to play the wav file in segments of 5 seconds.

In my code, I included a 'Pause' command in the point of segmenting the wav in 5 seconds window, which works when im running the code without the gui figure. Supose this button 3 is called 'Next sample' and what i want is the user press that button and hear the first 5 seconds. Then when he press again, the next 5 seconds are played and we can repeat this process until the wav file ends.

Now, my problem is: The user can play a sample of 5 seconds and then press the button of denoising again, and maybe he wants to continue hearing the next 5 seconds of the wav, that's why that 'pause' command is not working for what i want to do. What i need is to play 5 seconds and stay in that point but without that pause comand. Then whenever the user wants to play the next 5 seconds, he/she press the 'next sample' button again and hears the next 5 second.

Any ideas? I hope i explained the situation in a way you guys can understand me.

Thanks!

2 个评论
显示无隐藏无

Walter Roberson 2014-1-26

I do not understand why you have included the pause() ?

Reeki 2014-1-26

在 MATLAB Online 中打开

Because in my code i have a for, in that 'for' i take the 5 seconds window, show spectrogram and plot those 5 signals, if I dont wirte that pause, i dont have any time to see the spectrogram of those 5 seconds.

Then when the user finishes to see the specgram he press any button and see next 5 seconds.

Something like:

    for i=1:length(indfin),
        next=output_signal(indini(i):indfin(i));
        subplot(211)
        t=[0:(length(next)-1)]*(1/fs);
        plot(t,next)
        xlabel('tiempo(seg)')
        subplot(212)
        [ysa,f,t,p] = spectrogram(next,2*1024,2*1000,512,fs);
        surf(t,f,10*log10(abs(p)),'EdgeColor','none');
        axis xy; axis tight; colormap(jet); view(0,90);
        xlabel('Tiempo');
        ylabel('Frecuencia (Hz)');
        soundsc(next,fs);
        pause
    end

请先登录，再进行评论。

请先登录，再回答此问题。

Answer 1

Walter Roberson 2014-1-26

0
链接

此回答的直接链接

https://ww2.mathworks.cn/matlabcentral/answers/113750-pushbotton-which-can-not-be-controled-with-a-pause-command#answer_122251

在 MATLAB Online 中打开

In the place you initialize indfin, set

handles.curseg = 1;

and at the end of that routine,

guidata(hObject, handles);

Then in the callback that you currently have the "for" loop, change to

    i = handles.curseg;                 %new
    if i <= length(indfin)              %changed
        next=output_signal(indini(i):indfin(i));
        subplot(211)
        t=[0:(length(next)-1)]*(1/fs);
        plot(t,next)
        xlabel('tiempo(seg)')
        subplot(212)
        [ysa,f,t,p] = spectrogram(next,2*1024,2*1000,512,fs);
        surf(t,f,10*log10(abs(p)),'EdgeColor','none');
        axis xy; axis tight; colormap(jet); view(0,90);
        xlabel('Tiempo');
        ylabel('Frecuencia (Hz)');
        drawnow();                    %new
        soundsc(next,fs);
        handles.curseg = i + 1;       %new
      end