What's the difference between code?

It's a stupid question but these two line of code do the same thing wthere dt1 is a constant. Is it right?
prova= sum((out1.Y{i}(:,3:end)).^2)*dt1;
h=1;
for i=3:end;
y1=out.Y(:,i);
prova(h)=sum(y1.^2)*dt1;
h=h+1;
end;

 采纳的回答

Walter Roberson
Walter Roberson 2014-2-22
Yes, they appear to be, at least to the limits of round-off error.

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