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Adding each row to previous row in a vector-Not Cumulative

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Hajik zagori
Hajik zagori 2011-7-20
Hi , I've looked everywhere to find the solution for this but I couldn't find the answer. Here 's the problem. How to add each row in a vector with just the previous row? For example here is the process on this vector: A=[2 1 7 9 4] and the answer should be this vector: C=[3 8 16 13]
Thanks in advance.

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采纳的回答

Sukuchha
Sukuchha 2011-7-20
A=[2 1 7 9 4]; B = A(1:end-1)+diff(cumsum(A));
  1 个评论
Jan
Jan 2011-7-20
diff(cumsum(A)) ?! An expensive method to get: A(2:end). But in addition there is the danger of rounding errors, e.g. diff(cumsum([1e16, 1, 5])) is [0, 4] ! Therefore I strongly recommend not to use this.

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更多回答（3 个）

Jan
Jan 2011-7-20
Easier and faster:
B = A(1:end-1) + A(2:end)
  2 个评论
Sukuchha
Sukuchha 2011-7-21
Jan, your method is better ! i feel like stupid now ! I need to remember always solve problems in a simplier way !
Jan
Jan 2011-7-21
@Sukuchha: Often a direct translation of the human language is helpful. You've formulated your algorithm very clear already: "add each row in a vector with just the previous row". So you did solve the biggest part of the problem already. Most of the questions in this forum are much less clear.

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Paulo Silva
Paulo Silva 2011-7-20
C=arrayfun(@(x)plus(A(x),A(x-1)),2:numel(A))
or with a for loop
C=zeros(1,size(A,2)-1);
for x=2:size(A,2)
C(x-1)=A(x)+A(x-1);
end
C
Hajik zagori
Hajik zagori 2011-7-20
I used Sukuchha method and it worked.Thanks Sukuchha. But I should also thank Paulo Silva.

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