Problem with ''if''

2011 7 20
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Hi everyone, I have this variable:
values =
[] [1x27 char] [1x32 char] [1x28 char] [1x34 char]
and i want have a check for empty cells. I use :
if values[ ]==[ ]
....
end
But unfortunately....
??? Conversion to logical from cell is not possible. What can i do???

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Robert Cumming
Robert Cumming 2011-7-20

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cellfun ( @isempty, values )

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Jan
Jan 2011-7-20
CELLFUN('isempty') is remarkably faster than CELLFUN(@isempty).
alexis
alexis 2011-7-20
thank you for the answer but... I want my programme to stop when i have an non empty cell. I wan't to check the "values" and if the "values"is empty then i 'll continue my programme. Can you help me??
Robert Cumming
Robert Cumming 2011-7-20
presumably you have a for loop then so that you can stop/break? i.e.
for ii=1:length(values)
if isempty ( values{ii} )
break
end
end
Oleg Komarov
Oleg Komarov 2011-7-20
idx = cellfun('isempty',values);
find(~idx,1,'first')
Finds the location of the first non-empty.
alexis
alexis 2011-7-21
Thank you!!!

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