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Counting proportion of all rows taken by each unique row

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Ulrik Nash
Ulrik Nash 2011-7-20
Hi Everyone,
Suppose I have a matrix A, and I wish to determine the number of unique rows this matrix has. Then I could form B using:
B = unique(A,'rows')
So far, so good. This yields, say, 5 unique rows out of 100.
My problem is the following. Suppose, having found B, I wish to count for each of the 5 unique rows, how many rows are identical ... and then divided by the total number of rows in A, and sort. This will in this case give a 5 x 1 matrix summing to 100%.
How might this be done?
Regards,
Ulrik.

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采纳的回答

Jan
Jan 2011-7-20
X = ceil(rand(10, 10) * 5); % Test data
[B, I, J] = unique(X, 'rows');
n = size(X, 1);
H = histc(J, 1:n) / n
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Andrei Bobrov
Andrei Bobrov 2011-7-21
Hi Sean! I think so
X = ceil (rand (10, 10) * 5);% Test date
[B, I, J] = unique (X, 'rows');
H = histc (J, 1: length (I)) / size (X, 1)

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更多回答（1 个）

Andrei Bobrov
Andrei Bobrov 2011-7-20
more variant
[B, I, J] = unique(X, 'rows');
out = diff(find([1; diff(sort(J)); 1]))/length(J)

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