For loop, exceeded dimension error.
显示 更早的评论
Hi, this is most certainly an easy fix on which I seem to got myself stuck.
The loop should compare elements of an array and if it finds that they are equal it shall erase that row, next it shall recompute the size of the array and redo the comparison for the next element:
for ii=1:N
if (ii>1) && (ii<N)
i3=ii+1;
for jj=i3:N
if DD(ii,1)==DD(jj,1)
DD(jj,:)=[];
[N,M]=size(DD);
end
end
end
end
I get the following error:
??? Index exceeds matrix dimensions.
Error in ==> VB_CompDin2Darray at 29
if DD(ii,1)==DD(jj,1)
A pointer would be great. Cheers.
采纳的回答
Sean de Wolski
2011-7-20
Simply run the loop backwards so row 4 doesn't become row 3 when row 3 is deleted.
e.g:
for jj = N:-1:i3
%delete stuff
end
Now of course you're still best off (for speed) building an index vector and doing the whole delete once at the end.
idx = false(N-i3,1);
for jj = i3:N
if stuff
idx(jj) = true;
end
Mat(idx,:) = [];
end
4 个评论
Victor Buza
2011-7-20
Jan
2011-7-20
@Victor: The loop "for jj=i3:N" runs until the inital value of N, even if N is modified inside the loop. In most other programming languages modifying the limit inside the loop effect the number of iterations.
Sean de Wolski
2011-7-20
If you delete row 3; what happens to row 4? It becomes row 3! Now your matrix size is smaller, but the for-loop still wants to go to the ORIGINAL N.
Sean de Wolski
2011-7-20
Use unique, as Jan has suggested, anyway.
更多回答（1 个）
Jan
2011-7-20
Simple and efficient for large matrices:
[dummy, index] = unique(DD(:, 1));
DD = DD(index, :);
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2011-7-20
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