please see this code and tel me where is the problem beacause i don't find it

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hold on
%Nouveau programme le 21/02/2014
%%%%%%%%%%%%%Données physique du probleme%%%%%%%%%%%%%%%%%%%%%%%%%%
M=30; % masse de la poutre KG/ML??
EI=0.20*10^7; % Rigidité flexionnelle de la poutre N/m^2
ksi=0.4;
k=0.04*10^8; % rigidité du sol N/m^2
v=27.77; %vitesse m/s de chargement
n1=5;
c=0.05;
%nombre des modes
l=2*(3*pi)/2*(4*EI/k)^0.25; %m;longueur elastique de la poutre en m
%%%%%%%%%%%%%%%% Les conditions initiales %%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
v0=0.001; %m/s;vitesse initiale
T0=0.0001; %m déplacement initiale
t1=l/v; %temps de parcours de la longueuer elastique
ww1=0;
Q=1; %chargement en Newton
n=23; % Nombre de points d'analyse
f=-21:1:21; %creation du vecteu englobant toute la longueur élastique
beta=1;
for m=1:5
wn(m)=((((m^4)*(pi^4)*EI)/(M*(l^4)))+(k/M))^0.5; % Pulsation propre du systeme
wd(m)=(wn(m)^2-beta^2)^0.5; % pseudo pulsation
omega(m)=m*pi*v/l;
for i=1:n
f(i)=i;
xx(i)=l/(n-1);
xx1(i)=xx(i)*(i-1);
phi(i,m)=sin(m*pi*(xx1(i))/l);
for j=1:n
tt(j)=l/v/(n-1);
tt1(j)=tt(j)*(j-1);
x1(j)=v*tt1(j)
A1=2*Q/(M*l);
A2(m)=1/(wd(m)^4+2*((beta^2-wd(m)^2)*omega(m)^2)+omega(m)^4); %(((w_d(m))^4)+2*((((ksi*w_d)^2)+((w_n(m)^2)))*(mu(m)^2))+mu(m)^4);
A3(m)=2*beta*omega(m);
A4(m)=(omega(m)/wd(m))*(((beta)^2)-(wd(m)^2)+omega(m)^2);
A5(m)=-A3(m);
A6(m)=wd(m)^2-omega(m)^2;
T11(j,m)=exp(-beta*(tt1(j)));
T1(j,m)=A1*A2(m)*(T11(j,m)*(A3(m)*cos(wd(m)*tt1(j))+A4(m)*sin(wd(m)*tt1(j)))+A5(m)*cos(omega(m)*tt1(j))+A6(m)*sin(omega(m)*tt1(j)));
ww1(i,j,m)=phi(i,m)*T1(j,m);
end
end
end
for i=1:n;
for j=1:n;
ww1(i,j)=0;
for m=1:n1;
ww1(i,j)=ww1(i,j)+ww1(i,j,m);
%ww1(i,j) = sum(ww1(i,j,:));
end
end
end
for i=1:n
www(i)=ww1(i,j)
j=5
end
%plot(www,'g')
for j=1:n
www1(j)=ww1(i,j)
i=12
end
plot(www1,'r')
%plot(ww1(10,:))
  2 个评论
sihem chaib
sihem chaib 2014-3-12
thank you to be Interest; Yes the curve is breaken and i have to plot it fonction of x the beam lenght not fonction the number of element 'i' and

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采纳的回答

Youssef  Khmou
Youssef Khmou 2014-3-9
The program is functioning well , here is the result :
  2 个评论
Youssef  Khmou
Youssef Khmou 2014-3-12
you mean the result interpretation? ok the code is technically correct, the problem then is in the constants, verify the constants /or change : c, ksi and the velocity v .

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