0 个投票

Hi guys, I need an help with an if, it's the first time I use it and I am not sure if it works because if I write just & a note appears suggesting to use &&, but if I put && turns an error: ??? Operands to the and && operators must be convertible to logical scalar values.
the code is
for t=2:time
dWsim(t,:)=mu0+sigma0.*rndnum(t,:);
Wsim(t,:)=Wsim(t-1,:)+dWsim(t-1,:);
B(t,:)=1./((m-1)*(1-Wsim(t,:))).^(1/(m-1));
sigma(t,:)=sigma0.*((B(t,:)./B(1,:)).^m);
mu(t,:)=(sigma(t,:).^2).*(m./2.*B(t,:))+mu0.*((B(t,:)./B(1,:)).^m);
if(uninum(t,1:N)>0.5)&(mu(t,:)*(1/k)>uninum(t,1:N));
B(t,:)=B(t,:).*(1-k);
else
B(t,:)=B(t,:);
end
end
Can you please explain me in simple word swhich is the difference between & and &&
Thanks in advance
Gaia

请先登录，再回答此问题。

 采纳的回答

Jan
Jan 2011-7-27

1 个投票

The IF statenment is usually a scalar, otherwise an implicite ALL is performed. But perhaps you want an ANY:
if any(uninum(t,1:N)>0.5) && any(mu(t,:) / k > uninum(t,1:N))
or:
if all(uninum(t,1:N)>0.5 & mu(t,:) / k > uninum(t,1:N))
BTW: "* (1/k)" -> "/k" looks easier.

1 个评论
显示 -1更早的评论 隐藏 -1更早的评论

gaia buratti
gaia buratti 2011-7-27
thabks for the explanation na dfor the suggestion, it does not solve my problem but can be really useful in the future. Btw, thanks to you I understood the mistake, now seems working.
I know about the I was just copying a formula...

请先登录，再进行评论。

更多回答（0 个）

类别

在 帮助中心 和 File Exchange 中查找有关 Programming 的更多信息

标签

Community Treasure Hunt

Find the treasures in MATLAB Central and discover how the community can help you!

Start Hunting!

Translated by