How can I write the arguments of an anonymous function when programming?

2014 4 17
2 个回答
回答已采纳
更新时间：2014 4 18
5 次查看（30 天）

0 个投票

Good afternoon, my question arises when trying to programme the following code:
s(i+1)=NRK(Dt*f(tv(i+1),x)+s(i)-x,s(i));
Where NRK=NRK(function , numeric scalar) This was the symbolic implementation, with f=symbolic function, and x a symbolic array of unknowns.
The thing is that working with symbolic expressions can solve the issue, but this goes inside a loop, and symbolic tools slow down suprisingly the performance in a ratio of 100 times! However, anonymous functions do a perfect job.
My try was the following:
h=@([arguments (i.e. a, b, c, ...])Dt*f(t(i+1),[arguments (i.e. a, b, c,...])+s(i)-[a b c ...];
s(i+1)=NRK(@h,s(i));
How can I write these arguments? Is it possible? Thank you very much!

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per isakson
per isakson 2014-4-17
编辑：per isakson 2014-4-18

0 个投票

Doesn't the info in Anonymous Functions cover your case?
I'm guessing. Try something like to create the anonymous function
Dt = ???;
s = ???;
f = ???;
fh = @(a,b,c,ii) Dt*f( t(ii+1),a,b,c) + s(ii)-[a,b,c];
(What are Dt, s, f and t ?) And call it
fh(a,b,c,ii)
.
Added later: With varying number of input variables
Try
[fh1,fh2] = cssm( );
a = 'a1';
b = 'b2';
c = 'c3';
fh1( a )
fh1( a, b, c )
fh2( a )
fh2( a,b,c )
which returns
a1
a1, b2, c3
a1
a1, b2, c3
where
function [fh1,fh2] = cssm( )
fh1 = @(varargin) foo( varargin{:} );
fh2 = @(varargin) disp( strjoin( varargin, ', ' ) );
function foo( varargin )
disp( strjoin( varargin, ', ' ) )
end
end

更多回答（1 个）

Piockñec
Piockñec 2014-4-18

0 个投票

Thank you for your answer! Your solution is right, when writing an anonymous function for 3 variables (a,b,c). The problem is that the number of variables can vary (a,b,c,d,e,f...)... because x is a symbolic array of unkwnowns.
However, I have written the programme so that I do not need to solve my issue. Thank you again!!!

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