How to get independent gaussian distribution with zero mean?

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Xylo
Xylo 2014-4-25
评论： Xylo 2014-4-27
Here it follows the normal gaussian distribution.... b=1/sqrt(2*pi)/sigma*exp(-(x-mean).^2/(2*sigma^2)); b is a set,i.e a vector with size 10X1; I only know the mean, here this is zero. and sigma is the Standard Deviation. with respect to that I have some lemda values : lemda =
67.0536 16.5292 4.1281 2.2891 0.0000 0.0000 0.0000 0.0000 -0.0000 -0.0000

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回答（1 个）

Walter Roberson
Walter Roberson 2014-4-25
Are you attempting to create a description of a distribution? The stats toolbox has tools for that.
If you are attempting to get random values that follow a gaussian distribution with 0 mean, then
randn(10,1) * sigma

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