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Sum repetition in matrices

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Moe
Moe 2014-4-28
评论： Star Strider 2014-4-28
Hi everyone,
Suppose I have matrix d1, d2, d3, d4, d5:
d1 = [0 0 0 1;0 0 0 0]; % input data
d2 = [0 0 0 0;1 0 0 0]; % input data
d3 = [0 1 0 0;0 0 0 0]; % input data
d4 = [0 0 0 0;1 0 0 0]; % input data
d5 = [0 0 0 0;0 0 1 0]; % input data
and matrix c:
c = [10 12 14 5;1 4 9 15];
Then I want matrix m to be:
m1=c+d1
m2=c+d1+d2 % In other words, in each iteration, the new matrix d should be summed with previous one (same for rest of calculation)
m3=c+d1+d2+d3
m4=c+d1+d2+d3+d4
m5=c+d1+d2+d3+d4+d5
Can anyone please help me?
Note: matrix d is generated with another loop automatically which is dependent to output of matrix m (sum(sum(m)).
  2 个评论
Image Analyst
Image Analyst 2014-4-28
What's wrong with that way? Why do you need a loop?
Moe
Moe 2014-4-28
@ Image Analyst
Actually, I have over than 10,000 of matrix "d", and each of them will be calculated after calculation each matrix "m" (sort of convergence problem).

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Star Strider
Star Strider 2014-4-28
This works:
d(:,:,1) = [0 0 0 1;0 0 0 0];
d(:,:,2) = [0 0 0 0;1 0 0 0];
d(:,:,3) = [0 1 0 0;0 0 0 0];
d(:,:,4) = [0 0 0 0;1 0 0 0];
d(:,:,5) = [0 0 0 0;0 0 1 0];
c = [10 12 14 5;1 4 9 15];
m(:,:,1) = c;
for k1 = 2:size(d,3)+1
m(:,:,k1) = m(:,:,k1-1) + d(:,:,k1-1);
end
m = m(:,:,2:end) % Result for ‘m’

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