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finding nearest number in matrices

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sajad
sajad 2014-7-14
评论： sajad 2014-7-14
hi I have 2 matrices A and B.
A=[0 0.375 0.405 0.452 0.500 0.530 0.577 0.623 0.639 0.670 0.701 0.717 0.748 0.779]
B=0:01:end
I want to find nearest number of A to 0.1 and then to 0.2 and then to 0.3 and ...
in this case the nearest numbers to 0.1 and 0.2 is 0.but I want a program that find the nearest number to 0.1 and put that number away and then find the nearest number to 0.2 and so on.
can you help me?
  1 个评论
Jan
Jan 2014-7-14
编辑：Jan 2014-7-14
What have you tried so far?
"B = 0:01:end" is no valid Matlab syntax. Please edit the question and replace it by what you really want.

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采纳的回答

Image Analyst
Image Analyst 2014-7-14
What's the purpose of B? What is "end"?
Anyway, using A, try this:
clc;
A=[0 0.375 0.405 0.452 0.500 0.530 0.577 0.623 0.639 0.670 0.701 0.717 0.748 0.779]
for k = 1 : length(A)
[~, nearestIndex(k)] = min(abs(A - k/10));
end
% Display in command window:
nearestIndex
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Image Analyst
Image Analyst 2014-7-14
k is an index. Indexes can't start from 0 since they have to be integers starting at 1. However you can make another variable that is just k-1 if you want.
But anyway, that code doesn't use B like my latest code, so it's not right anyway.
sajad
sajad 2014-7-14
I used your first code.
thanks

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更多回答（1 个）

Jan
Jan 2014-7-14
编辑：Jan 2014-7-14
A = [0 0.375 0.405 0.452 0.500 0.530 0.577 0.623 0.639 0.670 0.701 0.717 ...
0.748 0.779]
B = 0:0.1:1; % Did you menat this?!
[value, index] = min(abs(bsxfun(@minus, A, B')))
  1 个评论
sajad
sajad 2014-7-14
No. thanks but previous answer is the thing I want.
I explained the exact thing in comment
thanks again

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